d=1100 km
v1=140 km/h
v2=120 km/h
t1=17h 33min
t2=18h 00min
Solution:
Trains will meet in time t far s1 from Paris. In the meeting time first train will pass s1=v1(t-t1), while the second train is far from initial position s2=v2(t-t2).
These two paths together make distance d: s1+s2=d whic makes
v1t-v1t1+v2t-v2t-v2t2=d

t=17h 33 min+ 4h 26 min = 21h 59 min
Place of meeting is far from Paris:
s1=v1(t-t1) =621,32 km
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